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Mathematics 21 Online
OpenStudy (anonymous):

Based on the histogram, how many students were included in the survey? What percentage of the students surveyed babysat for at least four hours last weekend? Show your work. A histogram titled Student Babysitting Hours Last Weekend is shown. The x-axis is labeled Hours and the y-axis is labeled Frequency Students. For zero to three hours, the frequency is fifteen. For four to seven hours, the frequency is ten. For eight to eleven hours, the frequencyis twenty. For twelve to fifteen hours, the frequency is fifteen.

OpenStudy (campbell_st):

add the frequencies for each column. This will give the total number

OpenStudy (anonymous):

so 60? @campbell_st

OpenStudy (campbell_st):

sounds right... looking at the information...

OpenStudy (anonymous):

is that it?

OpenStudy (campbell_st):

for the 2nd part find the percentage 0 to 3 hrs so its 15/60 * 100 = then the answer is 100% - the above answer..

OpenStudy (campbell_st):

or 45/60 * 100 either way gives the same result

OpenStudy (anonymous):

is it 400 or 133.333 repeated

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

nope 45/60 * 100 = 75%

OpenStudy (anonymous):

i dont understand @campbell_st

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