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factor the following sum of two cubes: z^3+27. so far i have: (z+3)(x^2....
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That is a good start :-)
Do you know the formula?
First write it as a "sum of two cubes."
z^3+3^3
is it (z+3)(x^2-3z+9)
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see a^3 +b^3 =(a+b)(a^2 -ab +b^2)
yup correct
do u want to factorise further...
then if w be the complex cube root of unity then w^2+w=-1 and w^3=1 hence a^2 -ab +b^2=a^2 +(w^2+w)ab +b^2w^3 =a^2 +w^2ab+wab +b^2w^3 =a(a+bw^2) +bw(a+bw^2) =(a+bw^2)(a+bw)
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