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Simplify the expression by using a double-angle formula. cos^2(theta/3) - sin^2(theta/3)
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use cos^2 x -sin^2x =cos2x
How this is new for me
I need help please
do u know cos(a+b)=cosa cosb -sina sinb now put a=x and b=x so we have cos(x+x)=cosx cosx -sinx sinx or cos2x =(cosx)^2 -(sinx)^2 or cos2x = cos^2 x -sin^2x
i will try it one moment
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so the answer will be cos(2.theta/3) right?
yup
are you sure?
Thanks matricked
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