Find the value of X, I'll draw it
@ganeshie8 could you please help me with this last one? This is the final one that's been stumping me in the practise package, I'll draw it
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its an isosceles trap
so two things :- 1) legs are equal (2x+3y = 12) 2) base angles are equal (30x+11y = 112)
solve both the equations
can you ? :)
So for the legs, would that be X=2? and I'm not exactly sure how to solve the second part, am I supposed to isolate the x or the y?
not exactly
you need to solve the system of two equations, you familiar with substitution method ?
2x+3y = 12 ---------(1) 30x+11y = 112------(2)
from (1), 2x+3y = 12 3y = 12-2x y = (12-2x)/3 substitute this y value in (2)
30x + 11(12-2x)/3 = 112
solve x
OH! Yes i do know the substitution method, ok I'll try again
good :)
Ok, so when i substituted x I got 3.33 and when i substituted for y I got 1.33
looks wrong
eh alright. I don't know what I did wrong
30x + 11(12-2x)/3 = 112 30x + 44-22x/3 = 112
30x-22x/3 = 68
90x-22x = 68*3
68x = 68*3
x=3
I don't get it at all :/ I thought I understood substitution but i guess not
So, the answer's 3? You solved the leg part, but how did you solve the other part? the same way?
hmm you just want the x right ?
or you weant 'y' also ?
No, just the x but you had given me two equations to solve,
or was that for the legs too? Sorry I'm confused :/
its okay, we have solved both the equations. after that we got x = 3 :- in above solution, we did below steps : 1) isolate y in equation(1) 2) substitute y in equation(2) 3) solve x
go thru it once again when u have time, im sure its easy for you :)
Thank you! I'll just have to look over the substitution method haha. Thanks again!
yes :) you wlcme !!!
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