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if y =25 -X^2 and 1 <(& equal to) x <(&equal to) 5, what is the smallest possible value of y? My answer is 0. Is that correct? If not, then can you explain to me step by step? Thanks!
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so you took the case that x=5?
Yup.
well yeah, that'll give you zero y=25-5^2=0
All right thanks! I just want to make sure, because this SAT book doesn't provide answers. lol -o-
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