Question

Write the equation of a hyperbola with vertices (-3, 0) and (3, 0) and co-vertices (0, -5) and (0, 5).

Answer 1

Given hyperbola has a horizontal transverse axis.
Its standard form: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of centre
For given hyperbola:
centre:(0,0)
length of horizontal transverse axis=6=2a
a=3
a^2=9
length of co-vertices or conjugate axis=10=2b
b=5
b^2=25
Equation:
x^2/9-y^2/25=1

Answer 2

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Answer 3

My Pleasure.

Answer 4

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Answer 5

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Answer 6

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Answer 7

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