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Square root 3 * cot(theta) - 1 =0
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\[\sqrt3*\cot \theta -1 = 0\] i hope this is what you mean
Yea I need to find all solutions
Unsure on how to do so
then sqrt 3 cot theta = 1 and cot theta = 1/ sqrt 3 then theta would equals cot inverse of 1/ sqrt 3
got it till now?
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How would I answer in terms of radians. I remember something about a K
So am I right. \[\Theta = k \pi + \frac{ \pi }{ 4\sqrt{3} }\]
Hmm :)
wait
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