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OpenStudy (anonymous):
How do you find the limit as x approaches infinity of the function (sin2x)/x?
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OpenStudy (anonymous):
OpenStudy (anonymous):
since sin(2x) is always between -1 and 1 when divided by infinity you get 0
OpenStudy (anonymous):
ooooh crap! it says \(\huge x\to \infty\) !!!
OpenStudy (anonymous):
i should learn to read, sorry what @litchlani said
OpenStudy (anonymous):
Ahahaha it's all good. Thanks for the help guys XD
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