Ok. So, we're going to solve for CD now. We're given the angle 30 degrees and the Hypotenuse of triangle ACD. CD is OPPOSITE of the angle given.
The hypotenuse equals 6.
\[\cos30 = \frac{ CD }{ 6 }\]
so
\[CD = 6\cos(30)\]
cos(30) =
\[\sqrt(3)/2\]
So.
CD = 3sqrt(3)
OpenStudy (anonymous):
Does this make sense?
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OpenStudy (anonymous):
OOPS!
OpenStudy (ttop0816):
yes it does!
OpenStudy (ttop0816):
wait...
OpenStudy (anonymous):
use sin! Not cos!
OpenStudy (ttop0816):
ye yea!! i was looking at that one more time too! haha
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OpenStudy (anonymous):
sin(30) = 1/2
OpenStudy (anonymous):
so CD = 3
OpenStudy (anonymous):
because CD = 6sin(30)
OpenStudy (anonymous):
sorry!
OpenStudy (ttop0816):
so would it be
square root of 3??
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OpenStudy (ttop0816):
these are the answers!
2
2 square root 3
square root 3
1.5
OpenStudy (anonymous):
Hang on.
OpenStudy (anonymous):
I'm going to draw what we've just done.
OpenStudy (anonymous):
|dw:1377409517752:dw|
OpenStudy (anonymous):
We have found CD. Now we have to find that angle and use trig once more to find DB
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OpenStudy (anonymous):
Do you know how we would find that angle?
OpenStudy (ttop0816):
would it be 45 degrees since it was a 90 degrees before spliting in half?
OpenStudy (anonymous):
Remember that the sum of all angles in a triangle is 180. In triangle ACD, we have one angle that is 90 degrees and another angle that is 30 degrees.
90+30+angle(ACD) = 180
This means that angle ACD would be 60 degrees right?
OpenStudy (ttop0816):
yess
OpenStudy (anonymous):
But we want DCB
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OpenStudy (anonymous):
Do you know what DCB is now?
OpenStudy (anonymous):
It's just ACD subtracted by 90 right?
OpenStudy (anonymous):
or 90 subtracted by ACD. :p
OpenStudy (anonymous):
90-60 = 30
OpenStudy (anonymous):
Does this all make sense?
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