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OpenStudy (anonymous):
find domain of f(x)=x+3/x+2
OpenStudy (anonymous):
anybody know how to do this
OpenStudy (jdoe0001):
what's say 25/0?
OpenStudy (jdoe0001):
can you actually get a value from \(\bf \cfrac{25}{0}\) ?
OpenStudy (anonymous):
no
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OpenStudy (jdoe0001):
so it's undefined?
OpenStudy (anonymous):
yes
OpenStudy (akashdeepdeb):
The domain can be ANY real number except -2
Because then it can be UNDEFINED!
Understood? :)
OpenStudy (jdoe0001):
\(\bf f(x) = \cfrac{x+3}{x+2}\)
if the denominator in a fraction becomes "0", then then the fraction becomes undefined, yes
thus when taking that into account for the DOMAIN, or values "x" can take
we have to keep in mind that the denominator of the rational mustn't be undefined
so the values "x" can take are the ones that won't make the denominator 0
OpenStudy (anonymous):
so (-1,infintity)?
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OpenStudy (jdoe0001):
look at AkashdeepDeb line above :)
OpenStudy (anonymous):
i get that but how do i say that
OpenStudy (jdoe0001):
if x= -2, then x+2 becomes
(-2) + 2 = 0
if you give "x" any other value, negative or positive, it won't make the denominator 0
OpenStudy (anonymous):
ok. so my domain is all real numbers other than -2
OpenStudy (jdoe0001):
well, I guess I could put it as \(\bf \large x \in \mathbb{R}; x \ne -2\)
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