Question

solve for x please : 2x^(2)+5x=8

Answer 1

2x^(2)+5x=8
2x^2+5x-8=0
Can't factor, need to use quadratic formula.
\[x=(-b \pm \sqrt{b^2 - 4ac})/2a\]
\[x=(-5 \pm \sqrt{5^2 - 4(2*-8)})/2*-8\]
\[x=(5 \pm \sqrt{89)})/16\]