A car travels on a bearing of 025 degrees along a straight path for 3.8km. Then it travels East for another 4.7km. Find: a) The total distance travelled North b) The total distance travelled East c) The distance between the initial and the final positions
Ive worked out a to be 3.4km and b to be 6.3km but am having trouble with c
Your answer is in parts a) and b). These two, which you have done correctly, can be used with the Pythagorean Theorem to calculate the distance requested in c).
lol omg I don't know why that never occured to me this question is part of a trig topic so pythagoras just didn't occur to me thanks you're a life saver
There is a reason why we have prerequisites. You are allowed to forget NOTHING you have taken before!! Good work.
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