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Solve the system by substitution. x + 3y = –4 2x + 2y = –8
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Solve for x and then plug that into the second equation
A ) x + 3y = -4 B) 2x + 2y = -8 A + B = ? then you can solve it...
3x+5y+-12
@PFEH.1999 it says by substitution :P
Oh sorry!I didn't read the question! SORRY!
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\[x + 3y = –4 \implies x= -3y-4 \implies 2(-3x-4)+2y=-8 \implies y=0\]\[\implies x=-4 \implies (x,y)=(-4,0)\]
x=-3y-4 2(-3y-4)+2y=8 Решите для Y
I have an error in the first line, should be -3y, not -3x.
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