Ask your own question, for FREE!
Algebra 11 Online
OpenStudy (anonymous):

(sinx)(cosx)(cos2x)

OpenStudy (anonymous):

(sin4x)/4

OpenStudy (anonymous):

i dont understand how you reached that answer

OpenStudy (anonymous):

2(sinx)(cosx )(cos2x)/2 =(sin2x) (cos2x)/2= 2 (sin2x)(cos2x)/4 =(sin4x)/4

OpenStudy (anonymous):

Thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!