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Find the magnitude ||v|| and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j
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No k
?
no
The magnitude \(\|v\|\) is given by \(\sqrt{(-4)^2+(-3)^2}\).
I dont know how to find the direction angle but the magnitude i can help with ^ beat me to it
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answer options if it helps A. 5; 233.1° B. 7; 216.9° C. 5; 216.9° D. 5; 36.9°
To find the angle, it might help to draw it: |dw:1377553517180:dw|
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