Ask
your own question, for FREE!
Mathematics
8 Online
The image below shows two parallel lines cut by a transversal. Using the figure below, solve for x.
Still Need Help?
Join the QuestionCove community and study together with friends!
. What about the previous question
You bailed on me
i figured it out ^^"
Atleast close the previous before starting a new one
Still Need Help?
Join the QuestionCove community and study together with friends!
those two angles are supplementary, so they add to 180 degrees, which means (2x - 50) + (4x + 20) = 180
Well thanks for not telling me....
Goddamn
pak_asfand, I'm sure Kitteh didn't mean to do that on purpose
Ahh np it happens
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
Time flies doesn't it? I tried to not be the second squeaky wheel of the household and ended up hurting myself and others severely.
clllaaaaaire:
any tips? the quality isn't the best because I am using this site on my computer
Midnight97:
Kinda a roleplay story between me and my friend enjoy... Part one Forgive me for all the screenshots.
StevenisGhost:
what type of song should I make next, and will y'all go check out my new song on
Midnight97:
My drawing sure changed over the years look at these two pictures from 2024 to no
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
20 hours ago
12 Replies
2 Medals
2 weeks ago
2 Replies
0 Medals
2 weeks ago
2 Replies
1 Medal
1 week ago
6 Replies
2 Medals
2 weeks ago
6 Replies
1 Medal
3 weeks ago
3 Replies
0 Medals
3 weeks ago
0 Replies
0 Medals