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f(x)=x^2+5x-6 I'm stuck, please help me!
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1x^2+5x-6=0
(x+ )(x+ ) I think the factors are -3,2 but it's not working out!
the factors are actually 6 and -1 because for the middle term or the 5 to be there something that multiplies together to make the -6 has to add up to equal the 5
I didn't even think of that...
(x+6)(x-1) don't know how I missed it, thank you
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its no problem, glad i could help
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