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The sum of two numbers is 31. One number is 5 less than 2 times the other number. Find the two numbers.
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Can anyone help me out please?
(x-5)2y=31 ??
x+y=31 (x-5)+(2y)=31 I think so, am not sure tho.
do you know how to solve for y?
I just tried to solve for Y. I got everything over to the right except the y but didn't look right. I ended up with a fraction
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2y=31-(x-5) 2y=31-x+5 2y=26-x y=(26/2)-x/2 y=13-x/2
Thats what i got for y.
13?
\[\frac{ 13-x }{ 2 }\]
??
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13 minus x/2
what is X??
can anyone help me out??
how about: x-5=31 2y=31
x=26
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