How do I find the integral? *see attachment*

Question

usukidoll · Answer

attachment

amriju · Answer

Ur attachment has the graph drawn in it...If the graph is correct then its area should give you the integral

usukidoll · Answer

how do I find the area????!?!

anonymous · Answer

3-a1-1ad5-141= 10.716524

usukidoll · Answer

what the heck how?

anonymous · Answer

Did you factor the conjugal value of the exponent?

usukidoll · Answer

it's going from 1 to 5 should it be get the antiderivative of that equation and then f(5)-F(1) ... x.x.x.

usukidoll · Answer

??? I don't understand @shaagasda

anonymous · Answer

Usuki, he didn't follow the derivative law for conjugal exponents...

anonymous · Answer

Don't confuse him lol....

anonymous · Answer

The answer is 10.716524....

anonymous · Answer

Pay more attention in class lol

usukidoll · Answer

I did plug in all the values of x from 1 to 5 and I did draw the graph. Now, the integral part x.x.

anonymous · Answer

Lol... that's like doing it in long division format... Never mind, I'm done lol.

anonymous · Answer

My answer was correct.

amriju · Answer

you have the maximum value of the function as 3...and clearly...the eqn is one degree so its the graph of a straight line...Now the function covers area from 1 to 5 only..so shouldn't the area be 1/2*3*4 thats 6??

anonymous · Answer

Try it on your TI-84...

amriju · Answer

sorry 0.5*3*5=7.5... would that be wrong??..@shaagasda

anonymous · Answer

Fine... I'll take it...

usukidoll · Answer

it's called I'm trying to refresh my memory on an old topic!

amriju · Answer

well then...check the answer and see if it matches

usukidoll · Answer

but why is it 0.5X3X5? Am I taking the area of a triangle of something....ooohhh 1/2 (base)(height)