Question

(4x-1)(-2x-3)+(1-4x)(3x+2)+16x^2=1

Answer 1

Can I show you how I would solve the question?

Answer 2

As long it is right, do as you wisch

Answer 3

*wish.

Answer 4

Right then, using the FOIL method on (4x-1)(-2x-3) gives us:
-8x^2 - 12x + 2x +3
=-8x^2 -10x + 3.

Answer 5

I have got the same.

Answer 6

Good, now using it on (1-4x)(3x+2) gives: 3x + 2 - 12x^2 - 8x.
= - 12x^2 - 5x + 2.

Answer 7

5(-4x^2-3x+1)

Answer 8

Now the equation looks like: -8x^2 -10x + 3 - 12x^2 - 5x + 2 + 16x^2 = 1
therefore -4x^2 - 15x + 5 = 1
tf 4x^2 + 15x - 4 = 0

Answer 9

tf 4x^2 + 16x - x - 4 = 0
tf 4x(x + 4) - 1(x + 4) = 0
tf (4x -1)(x+4) = 0
tf 4x -1 = 0 or x + 4 = 0
tf x = 1/4 or x = -4

Answer 10

Thank you.

Answer 11

You're welcome :)