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ln(y+6) - ln(4)= x+ln(x); solve for y... please help??(:
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write x + ln(x) as lne^x +lnx Now use lna+lnb = ln(a*b) and lna-lnb=ln(a/b)
so, ln (y+6)/4 = ln(x)+ ln(x) ..?
NO ln (y+6)/4 = ln (e^x*x)
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