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sin(xy)=x+y, what is dy/dx?
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sin(xy) = x (y + x*dy/dx)*cos(xy) = 1 y*cos(xy) + x*dy/dx*cos(xy) = 1 x*dy/dx*cos(xy) = 1 - y*cos(xy) dy/dx = (1 - y*cos(xy)) / (x*cos(xy)) dy/dx = 1/[x*cos(xy)] - y/x = (1/x)(sec(xy) - y)
bro its x+y
I know that. But why did you ask if you knew that answer
no its sinxy= x+y, not sinxy=x. you just copied it off of yahoo
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