MO bisects angle LMN, m ∠ LMN = 6x - 28, m ∠ LMO = x + 34. Find m ∠ NMO.

Question

anonymous · Answer

58 right?

raden · Answer

i cant login, can you make a diagram here ?

anonymous · Answer

Can you help me with another? I figured this one out.

raden · Answer

i'll try

anonymous · Answer

If T is the midpoint of line SU, what are ST, TU, and SU?
ST = 20, TU = 20, and SU = 40 
ST = 80, TU = 80, and SU = 160
ST = 16, TU = 80, and SU = 160
ST = 102, TU = 102, and SU = 204

anonymous · Answer

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raden · Answer

oke, because T is the midpoint of line SU, then satisfies :
ST = TU
5x = 3x + 32 (solve for x)
5x - 3x = 32
2x = 32
x = 32/2
x = 16
now subtitute the value of x = 16 into the equations of
ST = 5x = 5 (16) = 80 and 
TU = 3x + 32 = 3(16) + 32 = 48 + 32 = 80 also
SU = ST + TU = 80 + 80 = 160

anonymous · Answer

So 16, 80, 160?

raden · Answer

no, it is 
ST = 80, TU = 80, and SU = 160

anonymous · Answer

Ohh! I understand now because 80 + 80..