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find the indefinite integral of 9/2x+1
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|dw:1377693959752:dw|
?
Or is it \[\int\limits \frac{9}{2x+1}dx\]
YES that is the question.
You can integrate it directly, or by substituting u=2x+1
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When \[u=2x+1 \] \[du=2dx\] \[\frac{du}{2}=dx\] \[\int\limits\limits \frac{9}{2x+1}dx\] \[\int\limits\limits \frac{9}{u}\frac{1}{2}du\] \[\frac{9}{2} \int\limits \frac{1}{u}du\] Then finish it up
Thanks got it, and finished it off . Much appreciated.
Alright gl :)
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