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Solve x2 + 9x + 20 = 0. x = 2, x = 10 x = −2, x = −10 x = −5, x = −4 x = 5, x = 4
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Any ideas?
nope
$$\huge x^2 + 9x + 20$$
x=-5,-4
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You take get \(a\), \(b\), and \(c\). Then, to find \(x\): \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
So \[x = \frac {-9 \pm \sqrt {9^2 - 4 * 1 * 20}} {2 * 1}\]
Is it A
I gave you a formula with no variables. Just take a calculator and calculate it.
Is it B
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Calculate it.
I can tell you that it's C(x = -5, x = -4)
@harliedanielfrye ?
Yeah that i was gonna say
Write the formula down please. That way you can just look at it when you need it.
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well my sister just toke so no need
What does that even mean?
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