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If f(x) = 3x + 1 and g(x) = 2x − 4, find f[g(2)]. 25 4 0 1
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you have to find f[g(2)] first solve g(2), by plugging 2 on function g(x) for the value of x
ok then
what do you get ?
4
let see f(x) = 2x-4 let substitute the x for 2 2(2) - 4 4 - 4 = 0
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since you have that g(2) = 0 now substitute the 0 for the x on function f(x)
-4
let see f(x)= 3x +1 substitute the 0 for the x 3(0) +1 = ???
o i was doin 2(0)-4
that is function g(x),
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o so its 1
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