Question

Solve the system of the quadratic equation y=x^2-2x+2

Answer 1

(x-2)(x-1)

Answer 2

equal it to zero

Answer 3

i would complete the square
you will see two complex solutions

Answer 4

\[x^2-2x+2=0\]subtract 2 from both sides
\[x^2-2x=-2\] then take half of \(-2\) to get \(-1\) square it and get \(1\) and complete the square as
\[(x-1)^2=-2+1=-1\]

Answer 5

take the square root to get
\[x-1=\pm i\] and so
\[x=1\pm i\]