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In set builder notation how do you write the solutions of 5+ d < 8 -
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\[5+ d \le 8\]
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Well, \(5+d \leq 8\). So \(d\leq3\) So d can be anything within the space 3 and below to negative infinity so in set notation it is: \[\{x\in R\phantom{.}|\phantom{.}-\infty\lt d \leq 3\}\] or \[\{x\in R\phantom{.}|\phantom{.}d\in (-\infty,3\phantom{.}\big]\phantom{.}\}\]
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