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solve the equation algebraically 3(3x-1)^2=21
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\[3(3x-1)^{2}=21\]
\[(3x-1)^{2}=7\]
\[3x-1=\sqrt{7}\]
\[3x=1+\sqrt{7}\]
\[x=\frac{ 1+\sqrt{7} }{ 3 }\]
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don't forget the \(\pm\)
\[x=\frac{ 1\pm\sqrt{7} }{ 3 }\]
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