Question

9^x - 6 x 3^x - 27 = 0 then x is

Answer 1

Start with x = 1

If that doesn't work, try x = 2

..and so on.

Answer 2

@yashkhatri

Answer 3

hint
assume 3^x = a and hence 9^x = (3^2)^x =(3^x)^2=a^2
the above equation reduces to a^2 -6a-27=0
first solve for a and hence for x......