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V=vo/k*Ca *integral 0-0.8 dx/(1-x^2) vo=2 l/s, Ca=1 mol/l and k=0.02 l(mol*s), how do i solve this integral?
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|dw:1377796016839:dw|
no its not x^2 its (1-x)^2
put (1-x)=t
then use log
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do u understand @mew55
wait. how does the log work out?
u dont mind drawing it to me?
u dont mind drawing it to me?
1/t^2 integration ?
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wait a sec.
its integral 1/(1-x)^2
|dw:1377797610521:dw|
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