Question

Determine Whether The Equation is always, sometimes, or never true.

question 1
6(x+1)=2(5+3x)

question 2
3(y+3)+5y=4(2y+1)+5

Answer 1

First you need to distrubute.
So let's start with the first one.
6(x+1)=2(5+3x)
6x+1=10+3x
-3x -3x
3x+1=10
-1 -1
3x =9
/3 /3
x=3
So it is sometimes true because they dont equal each other but it does have a solution

Answer 2

@christhebest123 do you think you understand it well enough to do the second one?

Answer 3

wouldnt it be 6x+6=10+6x @Broganleab

Answer 4

if we were distributing

Answer 5

Oh pellet I forgot the 2.
Yes that is my bad let me redo it
6(x+1)=2(5+3x)
6x+1=10+6x
-6x -6x
and the 6 cancels out so now you have
1=10
do you think that is always sometimes or never true?

Answer 6

never true

Answer 7

Yep so do the same for the second and if you fine a solution its sometimes true if there is no solution its never true and if one equals the other say like 17=17 then it is always true

Answer 8

thanks

Answer 9

welcome!