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OpenStudy (anonymous):
help please 50/x / 100/x^2+5x
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OpenStudy (anonymous):
\[\frac{50}{x}\times \frac{x^2+5x}{100}\] is a first step then factor and cancel
OpenStudy (anonymous):
\[\frac{50x(x+5)}{100x}=\frac{x+5}{2}\]
OpenStudy (anonymous):
that's the answer??
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