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Algebra 12 Online
OpenStudy (anonymous):

what is the sum of 1+2+3+...+385

OpenStudy (debbieg):

\[\Large 1+2+....+n=\frac{ n(n+1) }{ 2 }\]

OpenStudy (anonymous):

what number is n?

OpenStudy (anonymous):

n=385

OpenStudy (debbieg):

Yes, whatever the last number of the summation is. In your problem, it is 385. It's a general formula for the total of a sum of integers from 1 to any integer n. :)

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