draw two structures one straight chain and one ring of a carbohydrate with the chemical formula of (ch2o)6

Question

e.cociuba · Answer

For the chain:

...OH..H..OH..OH
......I.....I....I....I
R---C---C---C---C---CH2OH
......I.....I....I....I
.....H..OH..H...H  

Substitute the R with CHO (this is an aldehyde with a terminal carbonyl-group and an attached hydrogen)
carbonyl-group: C=O
The structure of the aldehyde is not linear!
note: remember that the C in the aldehyde stands right (connected with the last C) when you draw it.

For the ring form you should read about monosacharides and their cyclic forms.
Since you have 6 carbon atoms I guess the ring will be a pyranose ring (6 edges) with a ring oxygen (oxygen bridge). 
This can easily be looked up with a bit of research put into it.

goformit100 · Answer

First of all @tyler24732 : A Warm Welcome to 'Open Study'. Please Read CoC (compulsory to read by all "Open Study" users) : http://openstudy.com/code-of-conduct