Question

solve for x. a^2x^2+2ax+1=0 but "a" CANT =0

Answer 1

Make "a" a number that simplifies the problem

Answer 2

Try a=1

Answer 3

Use the quadratic formula.
a=a^2
b=2a
c=1

Answer 4

a^2x^2 = (ax)^2,

so (ax)^2 + 2ax + 1 could be factored as (ax + 1) (ax + 1)

Answer 5

\[x=\frac{-2a \pm \sqrt{(-2a)^2-4(a^2)(1)}}{2(a^2)}\]

Answer 6

\[x=\frac{-2a \pm \sqrt{0}}{2a^2}\]

Answer 7

\[x=\frac{-2a}{2a^2}=-\frac{1}{a}\]