Question

Simplify: (5a)(6b)(2c).


A. 13abc
B. a5b6c2
C. 5a + 6b + 2c
D. 60abc

Answer 1

(ab)(cd)(ef)=(abc)(def)=(abcfed)=(dfebca)
we can move these around
so

(5a)(6b)(2c)=5*6*2*a*b*c

Answer 2

(5*6*2)(a*b*c)

Answer 3

lol

Answer 4

a*b*c is the formula to solve this?

Answer 5

no formula, i was just simply saying it does not matter the number, since we are dealing with multiplication we can move things around

Answer 6

so would it be d

Answer 7

oh okay

Answer 8

yes

Answer 9

correct

Answer 10

thanks

Answer 11

yw