Question

What is the simplified form of the square root of the quantity 128 times n to the seventeenth power.?

8n8the square root of the quantity 2 times n.

4n8the square root of the quantity 8 times n.

2n8the square root of the quantity 8 times n.

8n8the square root of the quantity 4 times n.

Answer 1

\[\sqrt{128n^{17}}=\sqrt{2^7*n^{16}n}=(2^6*2^1*n^{16}*n)^{\frac{1}{2}}=2^3n^8\sqrt{2n}=8n^8\sqrt{2n}\]

Answer 2

thank you