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find the value of k such that the line that passes through (0,k) and (-k-1) has a slope of 1/2
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Use the point-slope formula: m = (y-y1)/(x-x1) Put the values of both the points and the slope and you'll get the value of k :) UNderstood? :D
\(\begin{array}{ll|ll} slope = \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1} \implies \cfrac{1}{2}\\ &(x_1,y_1)&(x_2,y_2)\\ &(0,k)&(-k-1)\\ \end{array}\)
|dw:1377891818100:dw|
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