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Find the slope of the tangent line to the curve 4x^2-2xy+2y^3=94 at the point (4,3) .
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Find the derivative and then plug in x = 4 and y = 3. That will be your slope of the tangent line to the given curve.
This involved implicit differentiation.
i found the derivative, but it wasn't right still?
after differentiating \[8x-2y-2x \frac{dy}{dx}+6y^{2} \frac{dy}{dx} = 94\] solving \[\frac{dy}{dx} = \frac{2y-8x+94}{6y^{2}-2x}\] plug in point (4,3) \[\frac{dy}{dx} = \frac{34}{23}\]
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