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(.01)^-1/2
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keep in mind that \(\bf a^{-n} = \cfrac{1}{a^n}\)
and that \(\bf \Large a^{\frac{n}{m}} = \sqrt[m]{a^n}\)
\[(0.01)^{-\frac{1}{2}}=(\frac{1}{100})^{\frac{-1}{2}}=(\frac{100}{1})^{\frac{1}{2}}=\sqrt{100}=10\]
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