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Precalculus
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Find cos θ if sin θ = -12/13and tan θ > 0.
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\(\bf sin(\theta) = -\cfrac{12}{13} \implies \cfrac{opposite}{hypotenuse} \implies \cfrac{b}{c}\\ c^2 = a^2 + b^2 \implies \sqrt{c^2-b^2} = a\) find "a" to get the cosine of the angle
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