Question

Can someone help me solve this radical equation.
√(2x-9)+√(2x+6)=3

Answer 1

Welcome to Openstudy :)

Answer 2

\[\begin{align*}\sqrt{2x-9}+\sqrt{2x+6}&=3\\
\sqrt{2x-9}&=3-\sqrt{2x+6}\\
2x-9&=\left(3-\sqrt{2x+6}\right)^2\\
2x-9&=9-6\sqrt{2x+6}+(2x+6)\\
-24&=-6\sqrt{2x+6}\\
&\vdots \end{align*}\]
Does that help?

Answer 3

Thank you this really helped.