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is there a shorter way to do this problem
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the problem is
Find the sum of the numbers from 1 to 100. 1 + 2 + 3 + ... + 100 A. 101 B. 1,001 C. 5,000 D. 5,050
There is a direct formula that gives you the answer! The sum of n consecutive natural numbers is n(n+1)/2 Where n is the number of terms! :)
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ya
Great! :)
thx alot
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