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Using the digits 0-9, determine how many 8-digit numbers can be constructed according to the following criteria: The number must be odd and at least 60,000,000; digits may be repeated
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So the number of 8-digit numbers at least 60,000,000 should just be \(99999999-60000000+1=40000000\). How many of these do you think are even? how many odd?
Still confused. The answer would be 20000000
half of those \(40000000\) numbers left are even, and half are odd, so we count \(20000000\) such numbers
okay thank you
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