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Sum of numbers between 4 and 100?
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add from \(1\) to \(100\) and then subtract \(1+2+3=6\)
\[SUM = \frac{ n(a_1 + a_n) }{ 2 }\] n is the number of terms (96). a1 is the first term (4) and an is the last term (100)
Simple trick\[\begin{array}{} S &=& 4&+&5&+&...&+&99&+&100 \\ S &=&100 &+& 99 &+& ... &+& 5 &+ &4 \\ S+S &=&104 &+& 104 &+&... &+& 104 &+&104 \\ 2S& =& 97 \times 104 \end{array}\]
my mistake. 97 terms :)
my mistake. 97 terms :)
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