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Write the quadratic function in vertex form. y = x2 + 4x + 7
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Think really hard on this: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)
Did you think about it, yet?
ok i think i hve an answer
y= (x + 2)2 + 3 @tkhunny
How did you find that?
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That is correct, btw. Half of the 4, and then squared, gives the piece we seek. Then from the 7, there was 3 left over. Excellent work!
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