Question

how do I solve the equation e^ { 2 x } - 7 e^ { x } +10 = 0?

Answer 1

let a = e^x
then you have
a^2-7a+10 = 0
(a-2)(a-5)=0
so
e^x-2 = 0 and e^x-5=0
e^x=2 and e^x = 5
can you do it now?

Answer 2

yes. thanks!

Answer 3

np