Question

Determine all values of k such that the graph of 2kx^2+2kx+k+1=0 intersects the x-axis exactly once.

Please show complete solution and answer

Answer 1

b2 - 4ac

when it is zero you get just ONE real solution
so

b^2-4ac=0
What is a, b and c?

Answer 2

@.Sam. i tried solving for a, b and c and ended up with -4K^2-8k=0 what do i do next?

Answer 3

@.Sam. sorry i meant i tried solving for k, not a, b and c

Answer 4

Yeah, just solve for k,
add both sides -4k^2,
4k^2=-8k
k=-2

Answer 5

@.Sam. isn't it supposed to be completing the square? how did you get 2 if there were k's on both sides of the equation?

Answer 6

You divide both sides by k