Question

Why this code can't print on a straight line ? C++

Answer 1

what code?

Answer 2

#include <iostream>
using namespace std;
int num[15];
int u=0;
int main()
{


for(int i=0; i<15; i++)
{
num[i]= i;

if (num[i]%2 == 0)
{

cin >> num[i];
cout << num[i];
cout << " ";

}

else
{ cout << num[i];
cout << " ";
}
}
return 0;
}

Answer 3

I already answered this question.

Answer 4

I tried the new code but it doesn't seem to pring odd number sequence correctly , if you try it you will see

Answer 5

but the question said to only allow the array to except values in it's even positions.

Answer 6

your instructor will most likely set a break point on the cin line to see if it work correctly.

Answer 7

The exersise says to "ask the user to enter values only at even positions" which is like saying " odd positions should be a default sequence from 1 to 15 (picking only the odds) since the first part of the exersise is this a) Declare an array called “Num” with 15 integers.

Answer 8

Another example which I solved: c) Change all the items of the array with an ODD position to -1

Answer 9

But the even positions stay intact regardless

Answer 10

#include <iostream>
using namespace std;

int num[15];

int main()
{
for (int i=0; i < 15; i++)
{
//this line checks the index of the array
//because i is used as the index
if (i % 2 == 0)
{
cin >> num[i];
cout << num[i] << endl;
}
}
return 0;
}

This works I have checked the code myself

Answer 11

for the odd part you would just check for numbers with remainders then assign -1 to the spots with the remainders
num[i] = -1;

Answer 12

Also all code can be put on a straight line as long as the syntax is correct.

Answer 13

a compiler ignores blank space during the scanning process.

Answer 14

Although it would be highly irrational to put all code on one line.

Answer 15

If you put ``` above and below a code block, it does code high lighing and allows it to be copied properly. There are also code pasting services, like http://dpaste.com These two things can make it easier for people to help you.